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4.9x^2-5.142x-1=0
a = 4.9; b = -5.142; c = -1;
Δ = b2-4ac
Δ = -5.1422-4·4.9·(-1)
Δ = 46.040164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.142)-\sqrt{46.040164}}{2*4.9}=\frac{5.142-\sqrt{46.040164}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.142)+\sqrt{46.040164}}{2*4.9}=\frac{5.142+\sqrt{46.040164}}{9.8} $
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